With some people we were discussing powers of complex
numbers.

An identity at best "counterintuitive". $$e^i = (e^i)^{(2\pi/2\pi)} = (e^{2\pi i})^{1/2\pi} = 1^{1/2\pi} = 1$$

lol ;)**3.14**.2013

An identity at best "counterintuitive". $$e^i = (e^i)^{(2\pi/2\pi)} = (e^{2\pi i})^{1/2\pi} = 1^{1/2\pi} = 1$$

lol ;)

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